(1/5)^(x-5)=25^(3x+2)

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Solution for (1/5)^(x-5)=25^(3x+2) equation: 



(1/5)^(x-5)=25^(3x+2)

We move all terms to the left:

(1/5)^(x-5)-(25^(3x+2))=0



Domain of the equation: 5)^(x-5)!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)^(x-5)-(25^(3x+2))=0

We multiply all the terms by the denominator


(+1-((25^(3x+2)))*5)^(x-5)=0



We calculate terms in parentheses: +(+1-((25^(3x+2)))*5)^(x-5), so:

+1-((25^(3x+2)))*5)^(x-5

determiningTheFunctionDomain
-((25^(3x+2)))*5)^(x+1-5

We add all the numbers together, and all the variables

-((25^(3x+2)))*5)^(x-4

Back to the equation:

+(-((25^(3x+2)))*5)^(x-4)





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4





We calculate terms in parentheses: +(-((25^(3x+2)))*5)^(x-4), so:

-((25^(3x+2)))*5)^(x-4

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